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Fluorine And Strontium Ionic Compound

Strontium Fluoride is an Ionic compound , with formula #Sr# #F_2#.

Permit us encounter how we got the respond; Wait at the electronic organization of Sr and F cantlet.

Sr ( Z= 38) has electrons with following electronic configuration. 1#southward^ii#ii#south^ii#2#p^vi#three#s^ii#3#p^vi#4#s^ii#3#d^x#4#p^6#5#southward^two#

It loses two electron in its 5s subshell to achieve stability and forms ion #Sr^(2+)#.

#Sr^(2+)# 1#due south^2#2#s^2#2#p^6#3#s^two#3#p^6#4#southward^two#three#d^10#4#p^vi#

F ( Z=9) on the other manus has nine electrons and wants to gain one more electron to achieve stable noble gas configuration.Fluorine atom on gaining one electron forms negative fluoride ion, #F^-# ion.

F( Z=ix) = 1#s^2#2#due south^ii#ii#p^5#

#F^-# = i#southward^2#2#south^2#two#p^6#

Two Fluorine atoms gains one electrons each ( total of 2) from one Sr atoms, each Sr atom loses 2 electrons ( one each) to two chlorine atoms , in this process each Sr atom becomes #Sr^(2+)# ion and each fluorine cantlet later gaining one electron becomes #F^-# ion.

so in all we accept one #Sr^(2+)# ions and 2 fluoride #F^-# ions.
and so the formula becomes Sr#F_2#.

Look at the electronic arrangement of Ca and North atom.

Ca ( Z= 20) has 20 electrons with following electronic configuration. 1#s^2#two#southward^ii#2#p^six#3#south^2#3#p^6#4#s^ii#.

It loses two electron in its 4s subshell to achieve stability and forms ion #Ca^(two+)#.

#Ca^(2+)# = 1#due south^2#two#s^two#2#p^vi#iii#s^ii#3#p^6#

Northward ( Z=7) on the other paw has 7 electrons and wants to gain 3 electrons to achieve stable noble gas configuration.Nitrogen cantlet on gaining three electrons forms negative nitride ion, #N^-iii# ion.

Northward ( Z=7) = i#due south^2#2#s^2#2#p^3#

#North^-iii# = ane#s^2#2#s^2#two#p^half dozen#

Two Nitrogen atoms gains iii electrons each ( total of 6) from three Ca atoms, each Ca atom loses ii electrons (total of six) to two Nitrogen atom , in this process each Ca cantlet becomes #Ca^(two+)# ion and nitrogen atom after gaining 3 electrons becomes #N^-iii# ion.enter image source here

and so in all we have three #Ca^(2+)# ions and two nitride #N^-3# ions.
so the formula becomes #Ca_3# #N_2#.

Fluorine And Strontium Ionic Compound,

Source: https://socratic.org/questions/what-are-some-examples-of-ionic-formulas

Posted by: houptannothe.blogspot.com

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